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8-11-20 ROBERT-JAMES&ASSOCIATES,Inc. Sht 3 of 5 <br /> Tensile Stress in Concrete.- (psi.) ft:= rwh-12)- ft=293.199 > (�Ft= 178.01 <br /> SW - REBAR REQUIRED FOR STRESS <br /> Design of Reinforcing Steel in Footing <br /> Moment for USD Design: Mu:= 1.7-Mh Mu=56372.085 <br /> d:= [(bl-12)-.80] L <br /> F(b 1-12)2—8.625] d= 11.513 <br /> To Plot for"j Mu-12 <br /> u coeff:=. coeff =0.071 ju:= 0.83 <br /> fc-bl-12-d 2 <br /> Use yield strength of direct bury pipe to check. <br /> Yield Strength of Pipe: (psi.) fy:= 42000 <br /> Required Area: (in.2) As:= Mu-12 As= 1.873 <br /> ju.fy-d-0.90 <br /> Reinforcement Requirment As= 1.873 PipeArea=7.85 <br /> No rebar required with the direct bury pipe• <br /> Slab Parameters <br /> Height of slab: ft) HF:= 0.50 <br /> Width of slab: ft) WF:= 22.0 <br /> Length of slab: &) LF-.= 3.0 <br /> (Wind direction) <br /> Design of Reinforcing Steel in Slab: <br /> Rebar size: Number:= 3 <br /> (Number 2 <br /> RebarArea: (in.2) Area:= 1l 8 Area=0.11 <br /> 4 <br /> For length of slab: Asl:= 0.0012-HF-VVT-144 Asl= 1.901 <br /> Number required Asl = 17.21 Use eighteen 18 #3 Rebar x 2'-6"LG.equally spaced <br /> Area using 3"typical side clear thru center of slab. <br /> For width of slab: Asw:= 0.0012BY-LF.144 Asw=0.259 <br /> Number required: Asw 2.347 Use four(4)#3 Rebar x 21'-6"LG.equally spaced <br /> Area using 3"typical side clear thru center of slab. <br /> := [2.-[w-(dl —HF)-bl 2]-fl r(LF-WF-HF) <br /> Quantity -i +:N of Concrete: (yds.1 CY L 27.4 L 27 <br /> CY=2.386 Total <br /> Note: Keep bottom of pipes 3"from bottom of footings to create concrete cover for water exclusion. <br />